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发表于 2020-1-5 14:39:01
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<input type="file" id ="file1" runat= "server">
Dim filename, filepath As String
filename = Path.GetFileName(file1.PostedFile.FileName)
filepath = Server.MapPath("upload\news\") & filename
uploadfile.PostedFile.SaveAs(filepath)
Label1.Text = "上传成功!"
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