C++ 高手帮忙看个问题,急~~~

iskiller · 发表于 2020-2-20 15:30:01

一样的运行结果, 但是可以用其他方法来代替不? 总觉得这个CODE有点过长!!

#include <iostream.h>
#include <conio.h>
#include <iomanip.h>

//Fuction for print the function
void print31();//print function for the month that have 31 days
void print30();//print function for the month that have 30 days
void print28();//print function for the month that have 28 days
void date();//print function for the header for each date

int main () {

int optionM;
bool done = false;

//Initialise variable
optionM = 0;

while (!done) {
clrscr();//Clear the screen
//Obtain the user to select the month
cout <<"\n\nWelcome to programming";
cout <<"\n\nThis program is print out the calendar";
cout <<"\n\nPlease select the month";
cout <<"\n 1.  Janruary";
cout <<"\n 2.  February";
cout <<"\n 3.  March";
cout <<"\n 4.  April";
cout <<"\n 5.  May";
cout <<"\n 6.  June";
cout <<"\n 7.  July";
cout <<"\n 8.  August";
cout <<"\n 9.  September";
cout <<"\n 10. October";
cout <<"\n 11. November";
cout <<"\n 12. December";
cout <<"\n\nPlease select one month: ";
cin >>optionM;//Input option for month

//check if the user select the option month that are on month 1 and 3 and 5 and 7 and 8 and 10 and 12 which is 31 days month
if (optionM == 1 || optionM ==3 || optionM == 5 || optionM == 7 || optionM == 8 || optionM ==10 || optionM == 12) {
print31 (); done = true;
}//check if the user select the option month that are on month 4 and 6 and 9 and 11 which is 30 days month
else if (optionM == 4 || optionM == 6 || optionM == 9 || optionM ==11){
print30 (); done = true;
}//check if the user select the option month that are on month 2 that have 28 days month
else if (optionM == 2) {
print28 (); done = true;
}
else {
cout <<"\n\nError!!!! Please try again";
}
}

getch ();
return 0;
}

//functiion for print the function for user select the month that have 31 days
void print31 () {

//Initialise variable
int maxrow;
int maxcol;
int num = 1;
maxrow = 6;
maxcol = 6;
bool done = false;

while (!done){
//obtain user to select the start day in the week
cout <<"\n\nThis month have 31 days";
cout <<"\n\n 1. Sunday";
cout <<"\n\n 2. Monday";
cout <<"\n\n 3. Tuesday";
cout <<"\n\n 4. Wednesday";
cout <<"\n\n 5. Thursday";
cout <<"\n\n 6. Friday";
cout <<"\n\n 7. Saturday";
cout <<"\n\nPlease select one day: ";
int optionD = 0;//intput option day
cin >>optionD;
date();//print the header for sunday to saturday buy setting in print date.
cout <<"\n";
//check user select option day between 1 and 7 otherwise error and redo again
if (optionD > 0 && optionD <= 7){
for (int row = 1; row <= maxrow && num <= 31; row++) {//set up row to have 31 number in row
for (int  col = 0; col <= maxcol && num <= 31; col++){// set up column to have only 7 column
if (col +1 < optionD && !done) {//to set the start date of the week
cout <<"    ";//space for the start date
}
else {
if (num <=31) {//month have 31 day
cout <<setw(6) <<num++;//print out the number from 1 - 31 by 6 spaces
}
done = true;
}
}
cout <<"\n";//enter new line
}
}
else {
cout <<"\n\nError!!!! Please try again";
}
}
}
//functiion for print the function for user select the month that have 30 days
void print30 () {

//Initialise variable
int maxrow;
int maxcol;
int num = 1;
maxrow = 6;
maxcol = 6;
bool done = false;
while (!done) {
//obtain user to select the start day in the week
cout <<"\n\nThis month have 30 days";
cout <<"\n\n 1. Sunday";
cout <<"\n\n 2. Monday";
cout <<"\n\n 3. Tuesday";
cout <<"\n\n 4. Wednesday";
cout <<"\n\n 5. Thursday";
cout <<"\n\n 6. Friday";
cout <<"\n\n 7. Saturday";
cout <<"\n\nPlease select one day: ";
int optionD = 0;//intput option day
cin >>optionD;
date();//print the header for sunday to saturday buy setting in print date.
cout <<"\n";
//check user select option day between 1 and 7 otherwise error and redo again
if (optionD > 0 && optionD <= 7){
for (int row = 1; row <= maxrow && num <= 30; row++) {//set up row to have 30 number in row
for (int  col = 0; col <= maxcol && num <= 30; col++){// set up column to have only 7 column
if (col +1 < optionD && !done) {//to set the start date of the week
cout <<"    ";//space for the start date
}
else {
if (num <=30) {//month have 30 day
cout <<setw(6) <<num++; //print out the number from 1 - 30 by 6 spaces
}
done = true;
}
}
cout <<"\n";//enter new line
}
}
else {
cout <<"\n\nError!!!! Please try again";
}

}
}

//functiion for print the function for user select the month that have 31 days
void print28 () {

//Initialise variable
int maxrow;
int maxcol;
int num = 1;
maxrow = 6;
maxcol = 6;
bool done = false;

while (!done){
//obtain user to select the start day in the week
cout <<"\n\nThis month have 28 days";
cout <<"\n\n 1. Sunday";
cout <<"\n\n 2. Monday";
cout <<"\n\n 3. Tuesday";
cout <<"\n\n 4. Wednesday";
cout <<"\n\n 5. Thursday";
cout <<"\n\n 6. Friday";
cout <<"\n\n 7. Saturday";
cout <<"\n\nPlease select one day: ";
int optionD = 0;//intput option day
cin >>optionD;
date();//print the header for sunday to saturday buy setting in print date.
cout <<"\n";

//check user select option day between 1 and 7 otherwise error and redo again
if (optionD > 0 && optionD <= 7){
for (int row = 1; row <= maxrow && num <= 28; row++) {//set up row to have 28 number in row
for (int  col = 0; col <= maxcol && num <= 28; col++){// set up column to have only 7 column
if (col +1 < optionD && !done) {//to set the start date of the week
cout <<"    ";//space for the start date
}
else {
if (num <=28) {//month have 28 day
cout <<setw(6) <<num++; //print out the number from 1 - 28 by 6 spaces
}
done = true;
}
}
cout <<"\n";//enter new line
}
}
else {
cout <<"\n\nError!!!! Please try again";
}
}
}

void date() {
   clrscr();//clear the screen
//fuction to print the header for date sun to friday
   cout <<setw(6) << "Sun";
   cout <<setw(6) << "Mon";
   cout <<setw(6) << "Tue";
   cout <<setw(6) << "Wed";
   cout <<setw(6) << "Thu";
   cout <<setw(6) << "Fri";
   cout <<setw(6) << "Sat";
}

iskiller · 发表于 2020-4-27 19:00:02

其实就是输入月份和星期几, 然后就会显示日历从星期几排到最后, 按月份的天数来排~~

iskiller · 发表于 2020-4-27 19:15:01

我用同样的SWITCH来搞, 但是显示错误: 帮忙解决一下::

#include <iostream.h>
#include <conio.h>
#include <iomanip.h>

void days31();

void days();

int main () {
//declare and initialise variables
int month = 1;

//obtian the month in list
cout<<"\n\n January (1)";
cout<<"\n\n February (2)";
cout<<"\n\n March (3)";
cout<<"\n\n April (4)";
cout<<"\n\n May (5)";
cout<<"\n\n June (6)";
cout<<"\n\n July (7)";
cout<<"\n\n August (8)";
cout<<"\n\n September (9)";
cout<<"\n\n October (10)";
cout<<"\n\n November (11)";
cout<<"\n\n December (12)";
cout<<"\n Please select the month: ";
//user input a month
cin>>month;

switch (month){
//in those cases the days will be display 31 days
case 1: case 3: case 5:
      case 7: case 8: case 10:
      case 12:
days31();
break;
//in this case the days will be display 28 days
case 2:
cout<<"\n 28"; //days28();
break;
//in those cases the days will be display 30 days
case 4: case 6: case 9: case 11:
cout<<"\n 30";//days30();
break;
//other input will be show a error message
default:
cout<<"\n error messages!!! it is not correct input, please try again";
}

getch ();
return 0;
}
//this function will display 31 days in "days31"function
void days31() {

//obtian and initialise variables
int day=1;
int maxrow=6;
int maxcol=6;
int date=0;

//obtain the sharp of calendar from Sun to Sat
cout <<"\n 1. Sunday";
      cout <<"\n 2. Monday";
      cout <<"\n 3. Tuesday";
      cout <<"\n 4. Wednsday";
      cout <<"\n 5. Thusday";
      cout <<"\n 6. Friday";
      cout <<"\n 7. Saturday";
//user input the day

cout<<" \n\n Please Insert the day you wanted: ";
cin>>date;

days(); //display the dates from Sun to Sat

if (date > 0 && date <= 7){
for (int row = 1; row <= maxrow && day <= 31; row++)
for (int  col = 0; col <= maxcol && day <= 31; col++)

if (day <=31) {//month have 31 day
cout <<setw(6) <<day++;//print out the number from 1 - 31 by 6 spaces

}
else {
cout <<"\n\nError!!!! Please try again";
}

void days() {


   cout <<setw(6) << "Sun";
   cout <<setw(6) << "Mon";
   cout <<setw(6) << "Tue";
   cout <<setw(6) << "Wed";
   cout <<setw(6) << "Thu";
   cout <<setw(6) << "Fri";
   cout <<setw(6) << "Sat";

}

铸造师 · 发表于 2020-4-29 16:00:01

#include <iostream.h>
#include <conio.h>
#include <iomanip.h>

void days31();

void days();

int main () {
//declare and initialise variables
int month = 1;

//obtian the month in list
cout<<"\n\n January (1)";
cout<<"\n\n February (2)";
cout<<"\n\n March (3)";
cout<<"\n\n April (4)";
cout<<"\n\n May (5)";
cout<<"\n\n June (6)";
cout<<"\n\n July (7)";
cout<<"\n\n August (8)";
cout<<"\n\n September (9)";
cout<<"\n\n October (10)";
cout<<"\n\n November (11)";
cout<<"\n\n December (12)";
cout<<"\n Please select the month: ";
//user input a month
cin>>month;

switch (month){
//in those cases the days will be display 31 days
case 1: case 3: case 5:
      case 7: case 8: case 10:
      case 12:
days31();
break;
//in this case the days will be display 28 days
case 2:
cout<<"\n 28"; //days28();
break;
//in those cases the days will be display 30 days
case 4: case 6: case 9: case 11:
cout<<"\n 30";//days30();
break;
//other input will be show a error message
default:
cout<<"\n error messages!!! it is not correct input, please try again";
}

getch ();
return 0;
}
//this function will display 31 days in "days31"function
void days31()
{

//obtian and initialise variables
int day=1;
int maxrow=6;
int maxcol=6;
int date=0;

//obtain the sharp of calendar from Sun to Sat
cout <<"\n 1. Sunday";
      cout <<"\n 2. Monday";
      cout <<"\n 3. Tuesday";
      cout <<"\n 4. Wednsday";
      cout <<"\n 5. Thusday";
      cout <<"\n 6. Friday";
      cout <<"\n 7. Saturday";
//user input the day

cout<<" \n\n Please Insert the day you wanted: ";
cin>>date;

days(); //display the dates from Sun to Sat

if (date > 0 && date <= 7)
{
for (int row = 1; row <= maxrow && day <= 31; row++)
{
for (int  col = 0; col <= maxcol && day <= 31; col++)
{
if (day <=31)
{//month have 31 day
   cout <<setw(6) <<day++;//print out the number from 1 - 31 by 6 spaces

                     }

}
cout<<"\n";
   }
}
else
{
cout <<"\n\nError!!!! Please try again";
}

   }

void days() {


   cout <<setw(6) << "Sun";
   cout <<setw(6) << "Mon";
   cout <<setw(6) << "Tue";
   cout <<setw(6) << "Wed";
   cout <<setw(6) << "Thu";
   cout <<setw(6) << "Fri";
   cout <<setw(6) << "Sat";
   cout    << "\n";

}

iskiller · 发表于 2020-5-10 17:15:01

楼上,你给的那个程序,我输入3月份,然后输入星期1开始排31天, 还是从星期天开始排啊,没有变化啊~

iskiller · 发表于 2020-5-11 19:30:01

我要的结果是, 如果是选择3月份(31天), 再选择星期4. 然后出来的日历的1号就从第一周星期4开始排31天一直到最后一天完.

就好像:
SUN MON TUE WED THU FRI SAT
1 2 3
4 5 6 7 8 9 10
11 .. . .. ..

像上面那样排到31~~

iskiller · 发表于 2020-6-11 19:30:01

没有人知道啊? 帮帮忙啊

superandy · 发表于 2020-6-14 09:00:01

你自己找找，代码里有哪些是重复的，把它们封装到函数即可。如果你找不出重复，那么也就蛮好了，不用太在意代码长短。

q8399816 · 发表于 2020-6-18 10:15:01

各位大哥高手：
帮个忙，小弟有个问题是关于SPI拦截网络封包技术的，我现在已经拦截到了数据包，放到了文件中，但不知道如何过滤数据包了，我是用c++写的！请各位专家指点！！！非常感谢！！留个联系方式也好啊，象qq什么的？

iskiller · 发表于 2020-7-7 02:00:01

我要的结果是, 如果是选择3月份(31天), 再选择星期4. 然后出来的日历的1号就从第一周星期4开始排31天一直到最后一天完.

就好像:
SUN MON TUE WED THU FRI SAT
1 2 3
4 5 6 7 8 9 10
11 .. . .. ..

像上面那样排到31~~

高手帮帮忙啊~~

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