一个关于线程委托调用带参数的方法的问题！

archer1003

看下面代码：问题是下面代码中创建的线程委托调用的是Work（）这个方法，如果我想委托调用WorkOne（string msg）这个方法，这种情况应该怎么写？谢谢。
static void Main(string[] args)
{
        Thread currentThread = Thread.CurrentThread;
        Thread workThread = new Thread(new ThreadStart(Work));
        workThread.Start();
               
}

static void Work()
{
         Console.WriteLine("Hello Work");  
}

static void WorkOne(string msg)
{
         Console.WriteLine("Hello {0}",msg)
}

ooloife

楼上正解，ThreadStart是不带参数的，所以你可以把string msg设为全局变量来调用。

renalex

for(int i = 1; i <= 5; i++)
        {
            Thread t = new Thread(new ParameterizedThreadStart(Worker));

            // Start the thread, passing the number.
            //
            t.Start(i);
        }

private static void Worker(object num)
    {
        // Each worker thread begins by requesting the
        // semaphore.
        Console.WriteLine("Thread {0} begins " +
            "and waits for the semaphore.", num);
        _pool.WaitOne();

        // A padding interval to make the output more orderly.
        int padding = Interlocked.Add(ref _padding, 100);

        Console.WriteLine("Thread {0} enters the semaphore.", num);
        
        // The thread's "work" consists of sleeping for
        // about a second. Each thread "works" a little
        // longer, just to make the output more orderly.
        //
        Thread.Sleep(1000 + padding);

        Console.WriteLine("Thread {0} releases the semaphore.", num);
        Console.WriteLine("Thread {0} previous semaphore count: {1}",
            num, _pool.Release());
    }